On 26 Maj, 01:30, I V <[EMAIL PROTECTED]> wrote: > On Sun, 25 May 2008 15:49:16 -0700, notnorwegian wrote: > > i meant like set[pos], not iterate but access a specific position in the > > set. > > If you need to access arbitrary elements, use a list instead of a set > (but you'll get slower inserts). OTOH, if you just need to be able to get > the next item from the set, you can use an iterator: > > > now i have to do: > > s = toSet.pop() > > toSet.add(s) > > i = iter(toSet) > > s = i.next() > > > if i want to get the url of the next item in a set, how would i do that? > > i can do this with a list: > > > def scrapeSitesX(startAddress, toList, listPos): return > > scrapeSites(toList[listPos], toList, listPos+1) to use recursion with a > > list. > > i can work around that but it doesnt get as elegant. > > Do you have to use recursion here? Why not: > > for site in toList: > scrape(site)
i have tried both. anyway how do i concatenate sets? which i have to if use to funcions like you suggest. and also when iterating a set is there any other way to avoid exceptions than have a counter and compare to len(set). is there no method that cna check if iter != None -- http://mail.python.org/mailman/listinfo/python-list
