bukzor <[EMAIL PROTECTED]> wrote:
> That does, in fact work. Thanks! I'm a little sad that there's no
> builtin way to do it, owell.
>
> >>> def f(a, *args):
> ... print a
> ... for b in args: print b
> ...
> >>> import inspect
> >>> a = [2,3]
> >>> b = {'a':1}
> >>> inspect.getargspec(f)
> (['a'], 'args', None, None)
> >>> map(b.get, inspect.getargspec(f)[0])
> [1]
> >>> map(b.get, inspect.getargspec(f)[0]) + a
> [1, 2, 3]
> >>> f(*map(b.get, inspect.getargspec(f)[0]) + a)
> 1
> 2
> 3
If I saw that in my code I'd be wanting to get rid of it as soon as
possible!
I'd re-write f() to have all named arguments then the problem becomes
easy and the answer pythonic (simple dictionary manipulation)...
So instead of f(a, *args) have f(a, list_of_args).
The f(*args) syntax is tempting to use for a function which takes a
variable number of arguments, but I usually find myself re-writing it
to take a list because of exactly these sort of problems. In fact I'd
be as bold to say that f(*args) is slightly un-pythonic and you should
avoid as a user interface. It does have its uses when writing
polymorphic code though.
--
Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick
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