On 21 Mar 2005 17:16:18 -0800, integer <[EMAIL PROTECTED]> wrote: > you never deal directly with pointers in python. > in your case, you need to pass a mutable object as your 'buffer' > argument and perform operations on it such that 'buffer==data'. (for > example, you could use a list here.) > def testit( buffer ): > for i in range( len ): > buffer[A+i]=data[B+i] > for some constants A,B
That's unpythonic. The correct solution is to return the result. Anything else is trying to squeeze a C idiom into python for no gain. -- Stephen Thorne Development Engineer, NetBoxBlue.com -- http://mail.python.org/mailman/listinfo/python-list
