On May 20, 8:58 am, Paul McGuire <[EMAIL PROTECTED]> wrote:
> On May 20, 10:50 am, [EMAIL PROTECTED] wrote:
>
>
>
> > You don't need all those conditionals. A set differs from a list
> > precisely in the fact that each element is unique. And since the
> > function is expecting "s" to be an iterable object, it can be
> > constructed even without a for loop:
>
> > def compress(s):
> > return list(set(s))
>
> > That does the trick.
>
> Only if order does not need to be maintained. list(set(s)) will not
> necessarily keep the unique characters in the order they are seen.
> We'll have to check with the OP to see if this is important (I just
> assumed that it was because of the use of list comps).
>
> -- Paul
If order is important, you can use sorted() instead of list() like so:
def compress(s):
new = sorted(set(s), key=s.index)
return return ''.join(new)
~Simon
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