En Sun, 18 May 2008 02:49:03 -0300, Dick Moores <[EMAIL PROTECTED]> escribió:
> However, (please refer back to my original post)
> I want to keep the fstr, ultimately to be the
> string entered by the user who knows a bit about
> regex, but not how to use r' ' . Or
> alternatively, not assume any knowledge of regex,
> but build in some options, such as ignoring/not
> ignoring case, searching on just a string, or on
> a word. So I want to know how to build the user's
> fstr into regex. I apologize for not making this clear.
Ok, supose the user enters "joe (home)" and you want to build a regular
expression to find that words surrounded by space:
fstr = "joe (work)"
regex = r"\s" + fstr + r"\s"
This doesn't work exactly as expected, because "(" and ")" have a special
meaning in a regular expression; use re.escape:
regex = r"\s" + re.escape(fstr) + r"\s"
You may use "\\s" instead of r"\s", it's the *same* string. The r prefix is
just a signal, it says how to interpret the source code, not part of the string.
--
Gabriel Genellina
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