[EMAIL PROTECTED] wrote:
> Here's a example of Expressiveness of a Language.
>
> The following is Mathematica code that generates all possible
> equations of one term involving trig function. (tweak the funList and
> nesting level to define what ?all possible? means. if nesting level is
> 2, it takes about 20 minutes and returns a list of 2876 terms on a
> 2004 personal computer.
>
> << DiscreteMath`Combinatorica`
> funList = {Sin, Tan, Power[#, -1] &};
> Nest[Module[{li = #},
> (Union[#, SameTest -> (Module[{arg1 = #1, arg2 = #2},
> If[(*both expression contains both x and y*)
> And @@ (((((StringMatchQ[#, "*x*"] &&
> StringMatchQ[#, "*y*"]) &)@
> [EMAIL PROTECTED]) &) /@ {arg1, arg2})
> , SameQ[arg1, arg2 /. {x -> y, y -> x}],
> SameQ[arg1, arg2]]
> ] &)] &)@
> [EMAIL PROTECTED]@(Table[(Times @@ # &) /@ KSubsets[#, i], {i, 1,
> 2}] &)@[EMAIL PROTECTED], [EMAIL PROTECTED] &, funList, li]}
> ] &, {x, y}, 1];
> Select[%, ([EMAIL PROTECTED], "*x*"] &&
> [EMAIL PROTECTED], "*y*"]) &]
This does not even start running in Mathematica 6, let alone produce any
correct results. The first line was deprecated some time ago. I don't know
what is wrong with the rest of your program but it takes a while to produce
the empty list.
> The problem is this: generate a list of all possible math expressions
> using the following combination and rules:
>
> ? the math expression involves both x and y. (must have both present)
> ? you can use any of the 6 trig functions (you must, since the goal is
> to create all possibilities)
> ? The binary operations you can use are multiply, divide. (no addition
> or substraction, since that can make the result 2 terms)
> ? a sub-expression (such as x or y) can be replaced by a more
> complicated one. (i.e. you can nest)
Then your program should produce an infinite number of terms, e.g. x,
Sin[x], Sin[Sin[x]], ...
> The above i wrote in 2002. If there are requests, i'll translate the
> above code into emacs lisp.
A correct definition of what the program is supposed to do with a correct
implementation in any language would be a good start.
If you are trying to do what I think you are trying to do then this is a
trivial recursive definition in just about any language and it does not
take advantage of anything specific to Mathematica anyway.
--
Dr Jon D Harrop, Flying Frog Consultancy
http://www.ffconsultancy.com/products/?u
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