Bruno Desthuilliers <bruno.42.desthuilliers <at> websiteburo.invalid> writes:
> The problem here is that your first statement > > #>>> tasks = [[]]*6 > > creates a list (task) containing 6 references to the *same* (empty) list > object. You can check this easily using the identity test operator 'is': > > If you want 6 different list objects in tasks, you can use a list > comprehension instead: > > #>>> tasks = [[] for i in range(6)] > #>>> tasks > [[], [], [], [], [], []] > #>>> tasks[0].append(1) > #>>> tasks > [[1], [], [], [], [], []] > > HTH > -- > http://mail.python.org/mailman/listinfo/python-list Hi Bruno Thanks for clearing that up. Your example certainly works well, I will study list comprehension a little more. Many thanks Gabriel -- http://mail.python.org/mailman/listinfo/python-list
