David C. Ullrich <[EMAIL PROTECTED]> wrote:
> Becoming a fan of wxPython, but I can't stand
> what it does with error messsages
[snip]
> So I want to pop up a modal dialog on error.
[snip]
> Came up with a ridiculous hack involving both sys.stderr
> and sys.excepthook. Works exactly the way I want.
> Seems ridiculous - what's the right way to do this?
>
> Ridiculous_hack.py:
>
> import sys
> import wx
>
> def hook(*args):
> try:
> sys.__excepthook__(*args)
> finally:
> printer.Show()
>
> class ErrorDisplay:
> def __init__(self):
> self.buffer = ''
> def write(self, text):
> self.buffer = self.buffer + text
>
> def Show(self):
> wx.MessageDialog(None, str(self.buffer),
> 'Error:',wx.OK).ShowModal()
> self.buffer = ''
>
> printer = ErrorDisplay()
> sys.stderr = printer
> sys.excepthook = hook
Here is how I've done it in the past. It is a complete runnable
example :-
------------------------------------------------------------
#!/usr/bin/python
import wx
import sys
from traceback import format_exception
class TestApp(wx.Frame):
"""Test error handling"""
def __init__(self, parent, id, title):
wx.Frame.__init__(self, parent, -1, title, size=(200,200))
sys.excepthook = self.OnException
button = wx.Button(self, wx.NewId(), "Produce Error")
self.Bind(wx.EVT_BUTTON, self.OnClick)
self.Show(True)
def OnException(self, type, value, traceback):
"""
Called on OnException
"""
error_text = "".join(format_exception(type, value, traceback))
wx.MessageDialog(None, error_text, 'Custom Error:', wx.OK).ShowModal()
def OnClick(self, evt):
"Click with a deliberate mistake"
adsfsfsdf
if __name__ == "__main__":
app = wx.PySimpleApp()
frame = TestApp(None, -1, "Test")
app.MainLoop()
------------------------------------------------------------
--
Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick
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