Hi, This must be very basic, but how'd you pass the same *args several levels deep?
def func2(*args) print args # ((1, 2, 3),) # i want this to output (1, 2, 3) as func1! # there must be some better way than args[0]? def func1(*args): print args # (1, 2, 3) func2(args) func1(1,2,3) Thanks! Guillermo -- http://mail.python.org/mailman/listinfo/python-list