Ivan Illarionov <[EMAIL PROTECTED]> wrote:
>>> is there a better way than my solution? is mine ok?
>>
>> ['%s%s' % (not i%3 and 'Fizz' or '', not i%5 and 'Buzz' or '')
>> or str(i) for i in xrange(1, 101)]
>>
>> -- Ivan
>
> or, more correctly, if you actually need to "print":
>
> sys.stdout.write('\n'.join('%s%s' %
> (not i%3 and 'Fizz' or '', not i%5 aBuzz' or '')
> or str(i)
> for i in xrange(1, 101)))
I think the variant I came up with is a bit clearer:
for i in range(1,101):
print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else 'Buzz') or i
--
http://mail.python.org/mailman/listinfo/python-list
