On Sat, 10 May 2008 18:06:17 +1000, Arnaud Delobelle
<[EMAIL PROTECTED]> wrote:
"Kam-Hung Soh" <[EMAIL PROTECTED]> writes:
On Sat, 10 May 2008 07:19:38 +1000, <[EMAIL PROTECTED]> wrote:
> What would be the best method to print the top results, the one's
that
> had the highest amount of anagrams?? Create a new histogram dict?
You can use the max() function to find the biggest list of anagrams:
top_results = max(anagrams.itervalues(), key=len)
--
Arnaud
That is the biggest list of anagrams, what if I wanted the 3 biggest
lists? Is there a way to specific top three w/ a max command??
Built-in max() function only returns one result.
My solution is to make a sorted list and return last three items:
sorted((len(anagrams[key]), key) for key in anagrams.keys())[-3:]
Using the key= parameter of sorted() beats explicit DSU:
sorted(anagrams.itervalues(), key=len)[-3:]
Or even
sorted(anagrams.itervalues(), key=len, reverse=True)[:3]
Nice!
I just found out that DSU = Decorate-Sort-Undecorate idiom, from
http://wiki.python.org/moin/HowTo/Sorting.
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog";>Software Salariman</a>
--
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