dmitrey <[EMAIL PROTECTED]> wrote: > On 9 ôÒÁ, 13:17, Paul Hankin <[EMAIL PROTECTED]> wrote: >> On May 9, 11:04am, dmitrey <[EMAIL PROTECTED]> wrote: >> >> > list1 = ['elem0', 'elem1', 'elem2', 'elem3', 'elem4', 'elem5'] >> > and >> > list2 = [0, 2, 4] # integer elements >> >> > howto (I mean most simple recipe, of course) form list3 that contains >> > elements from list1 with indexes from list2, i.e. >> >> list3 = [list1[i] for i in list2] >> > > Ok, I use Python 2.5 but I try my code to remain Python 2.4 and > (preferable) 2.3 compatible. > Are there other solutions? > D. >
Did you try Paul's suggestion? Python 2.3.5 (#1, Oct 13 2005, 09:17:23) [GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-52)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> list1 = ['elem0', 'elem1', 'elem2', 'elem3', 'elem4', 'elem5'] >>> list2 = [0, 2, 4] >>> list3 = [list1[i] for i in list2] >>> list3 ['elem0', 'elem2', 'elem4'] -- http://mail.python.org/mailman/listinfo/python-list
