On Thu, 08 May 2008 15:42:07 +1000, dave <[EMAIL PROTECTED]>
wrote:
This is what i've came up with. My problem is that I can't get them to
properly evaluate.. when comparewords() runs it finds itself... Should
I have the keys of mapdict iterate over itself? Is that possible?
def annafind():
fin = open('text.txt') # file has one word per line
mapdic = {} # each word gets sorted & goes in here
for line in fin:
rawword = line.strip()
word = list(rawword)
word.sort()
mapdic[''.join(word)] = 0
return mapdic
def comparewords(): ***not working as intended
fin = open('text.txt')
for line in fin:
line = line.strip()
word = list(line)
word.sort()
sortedword = (''.join(word))
if sortedword in mapdic:
print line
On 2008-05-07 19:25:53 -0600, "Kam-Hung Soh" <[EMAIL PROTECTED]>
said:
On Thu, 08 May 2008 11:02:12 +1000, dave <[EMAIL PROTECTED]>
wrote:
Hi All,
I wrote a program that takes a string sequence and finds all the words
inside a text file (one word per line) and prints them:
def anagfind(letters): #find anagrams of these letters
fin = open('text.txt') #one word per line file
wordbox = [] #this is where the words will go
for line in fin:
word = line.strip()
count = 0
for char in letters:
if char not in word:
break
else:
count += 1
if count == len(word):
wordbox.append(word)
return wordbox
Now I'd like to modify the code to naturally find all anagrams inside
a
wordlist. What would be the best way to do this? Using Hints? Is it
possible to iterate over dict keys? How can I make a dict that maps
from a set of letters to a list of words that are spelled from those
letters? Wouldn't I need to make the set of letters a key in a dict?
As always - Thanks for helping someone trying to learn...
Dave
Suggestion: for each word, sort their characters and use them as the
dictionary key. If two words have the same combination of characters,
then they are anagrams. For example: "edam" and "made" are anagrams
because they have the letters 'a', 'd', 'e' and 'm'.
Refer "Programming Pearls" by Jon Bentley.
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog";>Software Salariman</
a>
Your code is always going to return the same list because every word is an
anagram of itself.
Tip: Create a list for each dictionary key, then add a word to the list if
that word is not in the list. So:
mapdic('adem') --> ["edam", "made"]
P.S. When replying, the convention is to add your response to the bottom,
not top of the message.
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog";>Software Salariman</a>
--
http://mail.python.org/mailman/listinfo/python-list
