On May 2, 9:44 am, NevilleDNZ <[EMAIL PROTECTED]> wrote:
> Below is a (flawed) one line RegEx that checks curly brackets (from
> awk/c/python input) are being matched. Is there a one liner for doing
> this in python?
>
> ThanX
> N
>
> re_open_close="(((\{))[^{}]*((?(0)\})))+"
> re_open_close=re.compile(re_open_close)
> tests="""
> { this is a test BAD
> { this is a test } OK
> { this is a test } { this is a test } OK
> { this is a test } { this { this is a test } is a test } OK
> { this is a test { this { this is a test } is a test } missing
> close BAD
> """.splitlines()[1:]
> for test in tests:
> if bool(re_open_close.search(test)) == bool(re.search("OK",test)):
> print "DETECTED:",test
> else:
> print "MISSED:",test
> [linux]$ python ./re_matching.py
> DETECTED: { this is a test BAD
> DETECTED: { this is a test } OK
> DETECTED: { this is a test } { this is a test } OK
> DETECTED: { this is a test } { this { this is a test } is a test }
> OK
> MISSED: { this is a test { this { this is a test } is a test }
> missing close BAD
Regexes can't count.
To check for balanced braces, you need to write code e.g.
# untested
def balanced_braces(s):
n = 0
for c in s:
if c == '{':
n += 1
elif c == '}':
n -= 1
if n < 0:
return False
return n == 0
HTH,
John
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