En Thu, 24 Apr 2008 00:32:37 -0300, Michael Torrie <[EMAIL PROTECTED]>
escribió:
Jeffrey Barish wrote:
Marc 'BlackJack' Rintsch wrote:
Please simplify the code to a minimal example that still has the
problem
and *show it to us*. It's hard to spot errors in code that nobody
except
you knows.
Here it is:
import copy
class Test(int):
def __new__(cls, arg1, arg2):
^^^^^^^
The exception is saying that copy.copy is not providing this 3rd
argument. I might be a bit dense, but what would arg2 be for? Isn't
arg1 supposed to be the object instance you are copying from? If so,
arg2 is superfluous.
I agree. In case arg2 were really meaningful, use __getnewargs__ (see )
import copy
class Test(int):
def __new__(cls, arg1, arg2):
return int.__new__(cls, arg1)
def __init__(self, arg1, arg2):
self.arg2 = arg2
def __getnewargs__(self):
return int(self), self.arg2
py> t = Test(3, 4)
py> print type(t), t, t.arg2
<class '__main__.Test'> 3 4
py> t_copy = copy.copy(t)
py> print type(t_copy), t_copy, t_copy.arg2
<class '__main__.Test'> 3 4
But note that subclassing int (and many other builtin types) doesn't work
as expected unless you redefine most operations:
py> x = t + t_copy
py> print type(x), x
<type 'int'> 6
py> t += t_copy
py> print type(t), t
<type 'int'> 6
--
Gabriel Genellina
--
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