Victor Subervi wrote: > Well, what I did was this: > > content = col_fields[0][14].tostring() > pic = "tmp" + str(i) + ".jpg" > img = open(pic, "w") > img.write(content) > print '<img src="%s"><br /><br />' % pic > img.close() > where I am incrementing i. Ugly. Stupid. But if it is the only way to do > it in python, and I do not want to invest the time doing it in php, > which I think would be prettier in this instance, then I guess it will > do. Your thoughts appreciated. > Victor > It is not the only way to do it on Python, it's not even an especially good way. But I suggest you either read what I have already written more carefully, or study HTTP and HTML until you understand what you are doing unnecessarily wrong. There is absolutely no need to save the images to the file store (otherwise there would be no point in having them in the database in the first place). You simply need to understand how to serve them dynamically.
regards Steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ -- http://mail.python.org/mailman/listinfo/python-list
