Thanks, this did the trick:
PyArg_Parse(ret,"O", &the_list);
if (PySequence_Check(the_list)) {
int size = PySequence_Size(the_list);
int *result = malloc(sizeof(int) * size);
int i;
for (i = 0; i < size; i++) {
PyObject *item = PySequence_GetItem(the_list, i);
if(PyInt_Check(item)) {
result[i] = PyInt_AsLong(item);
printf("value %d: %d", i, result[i]);
} else {
printf("Didn't work, NO INT");
}
}
}
kind regards,
Pieter
---------- Doorgestuurd bericht ----------
From: "Diez B. Roggisch" <[EMAIL PROTECTED]>
To: python-list@python.org
Date: Thu, 10 Apr 2008 12:23:56 +0200
Subject: Re: call python from c -> pass and return arrays/lists
Pieter wrote:
> Hi all,
>
> I'm trying to call a python function from c. I need to pass an
> 2D-array to python and the python function returns a 2D-list back to
> c. I googled arround and I found how to pass ints/strings/... back and
> forth, but didn't find anything on passing arrays.
>
> For an int it's as simple as this:
>
> PyArg_Parse(ret,"i#", &my_long);
>
> But I hacve no idea how to parse python lists to a c-array?
You return a list, parse that as object, and then work with the
sequence-protocol on them.
UNTESTED:
PyArg_Parse(ret,"o", &the_list);
if(PySequence_Check(the_list) {
int size = PySequence_Size(the_list);
int *result = malloc(sizof(int) * size);
for(int i = 0; i < size; i++) {
PyObject *item = PySequence_GetItem(the_list, i);
if(PyInt_Check(item)) {
result[i] = PyInt_AsLong(item);
} else {
return NULL;
}
}
Diez
--
Pieter Cogghe
Ganzendries 186
9000 Gent
0487 10 14 21
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