Sami schrieb:
> Hello,
>
> In the Python book that I am using to learn the language it says that
> the traceback.print_exc() can be used to stop exception propagation and
> make the program keep running.
>
> Here is a simple piece of code that I typed in to test this fact:
> ---------------------------------------------------------------------------
> import sys
>
> def Myexcepthook(etype, value, tb):
> print "in Myexcepthook\n"
> import traceback
> lines=traceback.format_exception(etype, value, tb)
> print "\n".join(lines)
> traceback.print_exc()
>
>
> sys.excepthook = Myexcepthook
>
> x = 1/0
>
> x = 78
>
> print x
> --------------------------------------------------------------------------
> The Output:
> --------------------------------------------------------------------------
> in Myexcepthook
>
> Traceback (most recent call last):
>
> File
> "E:\Home\Programming\Python\TryProjects\ExceptHandling1\Except2.py", lin
> 15, in <module>
> x = 1/0
>
> ZeroDivisionError: integer division or modulo by zero
>
> None
> --------------------------------------------------------------------------
>
> I never see the value 78.
>
> What am I doing wrong?
Trusting a wrong source. Or misinterpreting it.
Python 2.5.1 (r251:54863, May 2 2007, 16:56:35)
[GCC 4.1.2 (Ubuntu 4.1.2-0ubuntu4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
imWelcome to rlcompleter2 0.96
for nice experiences hit <tab> multiple times
>>> import traceback
>>> help(traceback.print_exc)
Help on function print_exc in module traceback:
print_exc(limit=None, file=None)
Shorthand for 'print_exception(sys.exc_type, sys.exc_value,
sys.exc_traceback, limit, file)'.
(In fact, it uses sys.exc_info() to retrieve the same information
in a thread-safe way.)
>>>
Nothing in there says that this would prevent the exception from being
propagated.
Diez
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