Peter Otten wrote: > Sami wrote: > >> Hello, >> >> I am new to Python. >> >> I tried to hook my own ExceptionPrintingFunction sys.excepthook but it >> does not work. >> >> This is what I wrote: >> ----------------------------------------------------------------------- >> import sys >> >> def MyOwnExceptHook(typ, val, tb): >> print "Inside my own hook" >> >> sys.excepthook = MyOwnExceptHook >> >> x = 1/0 >> ----------------------------------------------------------------------- >> This is what I get >> ----------------------------------------------------------------------- >> Traceback (most recent call last): >> File >> "E:/Home/Programming/Python/TryProjects/ExceptHandling1/Except5.py", >> line 8, in <module> >> x = 1/0 >> ZeroDivisionError: integer division or modulo by zero >> ----------------------------------------------------------------------- >> >> I never see "Inside my own hook" which tells me that the hook is not >> being called. What I really want to test is to stop the exception from >> propagating further and leave the program intact. >> >> What am I doing wrong? Please let me know if there are any other newbie >> groups that I should probably try in stead. > > Are you running your code from within idle? It wraps your script in > something like > > try: > # run script > except: > # show traceback > > (Have a look at InteractiveInterpreter.runcode() in code.py if you are > interested in the actual code) > > So your except hook never gets to see the exception and therefore won't be > invoked. Run your script from the commandline and you will see the > behaviour you expected. > > Peter >
Great!! Thank you. I have been trying since yesterday to get to the bottom of this. Does this mean that one should always use the command line to run a python program? Sami -- http://mail.python.org/mailman/listinfo/python-list
