Marco Mariani a écrit :
> Bruno Desthuilliers wrote:
> 
>> sig=lambda m:'@'.join(['.'.join([w[::-1] for w in p.split('.')]) for p 
>> in m.split('@')])
> 
> 
> Pff... you call that a quicksort?
> 

Nope, only somewhat obfuscated Python. And it seems it's at least 
obfuscated enough for you to believe it could be a quicksort 
implementation !-)

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