[EMAIL PROTECTED] wrote:
> Hi all,
>
> i have an XML file with the following structure::
>
> <r1>
> <r2>-----|
> <r3> |
> <r4> |
> . |
> . | --------------------> constitutes one record.
> . |
> . |
> . |
> </r4> |
> </r3> |
> </r2>----|
> <r2>
> .
> .
> . -----------------------|
> . |
> . |
> . |----------------------> there are n
> records in between....
> . |
> . |
> . |
> . ------------------------|
> .
> .
> </r2>
> <r2>-----|
> <r3> |
> <r4> |
> . |
> . | --------------------> constitutes one record.
> . |
> . |
> . |
> </r4> |
> </r3> |
> </r2>----|
> </r1>
>
>
> Here <r1> is the main root tag of the XML, and <r2>...</r2>
> constitutes one record. What I would like to do is
> to extract everything (xml tags and data) between nth <r2> tag and (n
> +k)th <r2> tag. The extracted data is to be
> written down to a separate file.
>
> Thanks...
You could create a generator expression out of it:
txt = """<r1>
<r2><r3><r4>1</r4></r3></r2>
<r2><r3><r4>2</r4></r3></r2>
<r2><r3><r4>3</r4></r3></r2>
<r2><r3><r4>4</r4></r3></r2>
<r2><r3><r4>5</r4></r3></r2>
</r1>
"""
l = len(txt.split('r2>'))-1
a = ('<r2>%sr2>'%i for j,i in enumerate(txt.split('r2>')) if 0 < j < l
and i.replace('>','').replace('<','').strip())
Now you have a generator you can iterate through with a.next() or
alternatively you could just create a list out of it by replacing the
outer parens with square brackets.
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