Hello,
Originally I posted this as a bug but it was shot down pretty quickly.
I am still mildly curious about this as I'm missing a bit of
understanding of Python here. Why is it that the following code
snippet:
def decorator( call ):
def inner(func):
def application( *args, **kwargs ):
call(*args,**kwargs)
func(*args,**kwargs)
return application
return inner
class DecorateMe:
@decorator( call=DecorateMe.callMe )
def youBet( self ):
pass
def callMe( self ):
print "Hello!"
DecorateMe().youBet()
Will not compile, giving:
Traceback (most recent call last):
File "badpython.py", line 10, in <module>
class DecorateMe:
File "badpython.py", line 11, in DecorateMe
@decorator( call=DecorateMe.callMe )
NameError: name 'DecorateMe' is not defined
Where if you change the "call=DecorateMe.callMe" to "call=lambda x:
DecorateMe.callMe(x)" everything goes along its merry way. Nesting the
call in a lambda seems to allow it to recognize the class definition.
Any ideas as to what is going on here (other than ugly code)?
Thank you,
Thomas Dimson
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