En Mon, 31 Mar 2008 09:30:00 -0300, Graeme Glass <[EMAIL PROTECTED]> escribió:
> On Mar 27, 11:01 am, Peter Otten <[EMAIL PROTECTED]> wrote: >> a b c aa ab ac ba bb bc ca cb cc aaa aab aac aba abb abc aca acb acc >> baa bab >> bac bba bbb bbc bca bcb bcc > > Here is a cool solution we came up with during a little interactive > session at our local meet up. > (http://www.python.org.za/pugs/cape-town/cape-town) > > s = 'abcdef' > ["".join([s[j] for j in range(len(s)) if x & (1 << j)]) for x in > range(1,2**len(s)) ] But it's doesn't generate the right sequence, and a lot of elements are missing. For 'abc': ['a', 'b', 'ab', 'c', 'ac', 'bc', 'abc'] It lacks ba, bb, ca, cb, cc, all b??, all c?? - see the sequence quoted above. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
