On Mon, Mar 31, 2008 at 12:24 PM, <[EMAIL PROTECTED]> wrote:
> How do I get a Rubik's cube translation out of this:
>
> >>> a= numpy.array([[0,1,2],[3,4,5],[6,7,8]])
> >>> a
> array([[0, 1, 2],
> [3, 4, 5],
> [6, 7, 8]])
> >>> a[:,0],a[:,1],a[:,2] #no good
> (array([0, 3, 6]), array([1, 4, 7]), array([2, 5, 8]))
> >>>
>
> I need [[ 6, 3, 0 ], [ 7, 4, 1 ], [ 8, 5, 2 ]].
>
> >>> c= numpy.array([[ 6, 3, 0 ], [ 7, 4, 1 ], [ 8, 5, 2 ]])
> >>> c
> array([[6, 3, 0],
> [7, 4, 1],
> [8, 5, 2]])
In [10]: numpy.rot90(a, 3)
Out[10]:
array([[6, 3, 0],
[7, 4, 1],
[8, 5, 2]])
Tim
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