On Mar 29, 11:45 pm, hdante <[EMAIL PROTECTED]> wrote: > On Mar 28, 10:47 pm, "aeneng" <[EMAIL PROTECTED]> wrote: > > > Hello everyone, > > Hi, > > Always avoid reinventing the wheel: > > from Numeric import array, cross_product > a = array([1, 2, 3]) > b = array([4, 5, 6]) > print cross_product(a, b) > > See: > http://numpy.scipy.org/ > http://www.scipy.org/ > > (hint: consider that many people want to multiply matrices) :-) > > > > > > > I am just starting to use python in numerical cacluation. > > I need you to help me to see what's wrong with the following piece of > > codes, which computes the cross product of two vectors and returns > > the result. u and v are two 3x1 matrix. > > > when I import the function, error message show like this>>> import cross > > > Traceback (most recent call last): > > File "<stdin>", line 1, in ? > > File "cross.py", line 8 > > ppp2=u[2]*v[0]-u[0]*v[2] > > ^ > > SyntaxError: invalid syntax > > > WHAT IS WRONG WITH MY CODE? > > > I appreciate your help. > > > ##here is the function definition. > > ##cross.py## > > def cross(u,v) > > """input two vectors u and v in 3-D space, > > output a cross product of vector w, in column or in row > > accordingly.""" > > ppp1,ppp2,ppp3=0.0,0.0,0.0 > > ppp1=u[1]*v[2]-u[2]*v[1] > > ppp2=u[2]*v[0]-u[0]*v[2] > > ppp3=u[0]*v[1]-u[1]*v[0] > > # store the result of the cross product in u > > u[0]=ppp1 > > u[1]=ppp2 > > u[2]=ppp3 > > return u #return the cross product of vector u x v. > > if __name__=="__main__": > > from cvxopt.base import matrix > > u=matrix([1.0,0.0,0.0],(3,1)) > > v=matrix([0.0,1.0,0.0],(3,1)) > > print cross(u,v) > > print "file name is %s" %__name__- Hide quoted text -
Bandwidth is really low; offload logic. I'd run some AI for the games so you can get a couple more triangles... plot.thicken() -- http://mail.python.org/mailman/listinfo/python-list
