En Wed, 19 Mar 2008 08:16:52 -0300, Beema shafreen
<[EMAIL PROTECTED]> escribió:
> i am trying to print the dictionary values and tuple in a same line as
> below
>
> print "\t".join(dict[a].values())+'\t'+"\t".join(b)
>
> Error I get is the TypeError,
> since i have misisng values in the dictionary. if i use exception i
> will
> miss those
> how should i print the data without missing the lines excluding the error
> separated by tab.
What is a? What is b? Their contents? I *guess* this is what you want:
a = {'some': 'values',
3.14: 'in a',
1234: 'dictionary'}
b = ('99', 'bottles', 'of', 'beer')
print '\t'.join(a.values()) + '\t' + '\t'.join(b)
The code above only works if all values are strings - else you could get a
TypeError. In that case, convert all items to string before joining:
a = {'some': 'values',
'in a': 3.14,
'dictionary': 1234}
b = (99, 'bottles', 'of', 'beer')
print ('\t'.join([str(value) for value in a.values()])
+ '\t'
+ '\t'.join([str(item) for item in b]))
If this is not your problem, please provide a complete example next time,
and the full exception traceback is very important too.
--
Gabriel Genellina
--
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