On Mon, 17 Mar 2008 10:40:43 +0000, Duncan Booth wrote:
> Here's a puzzle for those who think they know Python:
>
> Given that I masked out part of the input, which version(s) of Python
> might give the following output, and what might I have replaced by
> asterisks?
>
>>>> a = 1
>>>> b = ****
>>>> if a is b: print 'yes!'
> ...
>>>> b
> 1
>>>> type(b)
> <type 'int'>
I know it! Using CPython 2.5.2a0, 2.6a1+ and 3.0a3+::
>>> b = type('type', (type,), {'__repr__': lambda self:
... "<type 'int'>"})('int', (object,), {'__repr__':
... lambda self:"1"})()
>>> b
1
>>> type(b)
<type 'int'>
>>> 1 is b
False
What's my prize?
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