In article <[EMAIL PROTECTED]>, Steven Bethard <[EMAIL PROTECTED]> wrote:
Ron Garret wrote:
What I'm really trying to do is to create enumerated types such that if:
e1 = enum(lst) and v = e1(x)
then
(x in lst) and (e1[v] == x)
Use a class with __call__ and __getitem__:
py> class enum(object): ... def __init__(self, vals): ... self.vals = vals ... def __call__(self, val): ... return self.vals.index(val) ... def __getitem__(self, index): ... return self.vals[index] ... py> lst = 'abcd' py> x = 'b' py> e1 = enum(lst) py> v = e1(x) py> (x in lst) and (e1[v] == x) True
Yeah, except I actually left out one thing: I also want type(v)==e1.
Why? In Python usually you rely on duck-typing and not explicit type checks. What is it that you're trying to gain by asserting type(v) == e1?
STeVe -- http://mail.python.org/mailman/listinfo/python-list
