On Mar 13, 11:29 pm, Dave Kuhlman <[EMAIL PROTECTED]> wrote: > Arnaud Delobelle wrote: > > > 4. Both points above follow from the fact that foo.bar is really a > > function call that returns a (potentially) new object: in fact what > > really happens is something like > > Arnaud and Imri, too - > > No. foo.bar is *not* really a function/method call.
It is. The keyword here is 'descriptor'. Maybe reading this will help: http://users.rcn.com/python/download/Descriptor.htm > > > > Foo.__dict__['bar'].__get__(foo, Foo). > > > So every time foo.bar is executed an object is (or may be) created, > > with a new id. > > > HTH > > I appreciate the help, but ... > > Actually, it does not help, because ... > > My understanding is that foo.bar does *not* create a new object. All it > does is return the value of the bar attribute of object foo. What new > object is being created? A bound method. Compare the following: >>> foo.bar <bound method Foo.bar of <__main__.Foo object at 0x69850>> >>> Foo.__dict__['bar'].__get__(foo, Foo) <bound method Foo.bar of <__main__.Foo object at 0x69850>> >>> > If I have: > > class Foo(object): > def bar(self): pass > > And I do: > > foo = SomeClass() > > then: > > foo.bar > > should return the same (identical) object everytime, no? yes? No. This is what I explained in my original reply. > I'm still confused. That's because you need to adjust your understanding. -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list
