Thanks. I found this to work:
input_file=open('junkin.txt','r')
output_file=open('junkout.txt','w')
for (line_cnt, each_line) in enumerate(input_file):
output_file.write('%4d '%(line_cnt+1)+each_line)
output_file.close()
input_file.close()
I removed the print, but ran into trouble with zfill. I thought this might
be more difficult judging by a long ago experience with Java.
Chris wrote:
> On Feb 14, 1:29 pm, John Machin <[EMAIL PROTECTED]> wrote:
>> On Feb 14, 6:13 pm, Chris <[EMAIL PROTECTED]> wrote:
>>
>>
>>
>>> On Feb 14, 8:54 am, "W. Watson" <[EMAIL PROTECTED]> wrote:
>>>> See Subject. It's a simple txt file, each line is a Python stmt, but I need
>>>> up to four digits added to each line with a space between the number field
>>>> and the text. Perhaps someone has already done this or there's a source on
>>>> the web for it. I'm not yet into files with Python. A sudden need has burst
>>>> upon me. I'm using Win XP.
>>>> --
>>>> Wayne Watson (Nevada City, CA)
>>>> Web Page: <speckledwithStars.net>
>>> enumerate through the file which will yield you a counter (starting @
>>> zero so just add 1) and use the string function .zfill() to pad it out
>>> for you.
>>> eg.
>>> for (line_cnt, each_line) in enumerate(input_file):
>>> output_file.write(print ('%s '%(line_cnt+1)).zfill(5) + each_line)
>> (1) What's that "print" doing in there?
>> (2) zfill(5)? The OP asked for "up to 4 digits", not 5.
>> (2) As an alternative to str.zfill, consider using formatting:
>>
>> output_file.write('%04d %s' % (line_cnt+1, each_line))
>>
>> And what does "up to 4" mean? What does the OP want the 10000th line
>> to look like?
>
> print was a typo
> take a look at the string that is built before the zfill fires, it has
> a trailing space so it is correct. ;)
--
Wayne Watson (Nevada City, CA)
Web Page: <speckledwithStars.net>
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