Paul Rubin wrote: > James Stroud <[EMAIL PROTECTED]> writes: >> I defined a little debugging function called iterprint: >> >> def iterprint(thing): ... >> for x in thing: >> iterprint(x) > > of course this mutates the thing that is being printed. Try using > itertools.tee to fork a copy of the iterator and print from that. > I didn't look at the rest of your code enough to spot any errors > but take note of the warnings in the groupby documentation about > pitfalls with using the results some number of times other than > exactly once.
I can see I didn't explain so well. This one must be a bug if my code looks good to you. Here is a summary: - If I iterprint inside the loop, iterprint looks correct. - If I iterprint outside the loop, my generator gets consumed and I am only left with the last item, so my iterprint prints only one item outside the loop. Conclusion: something consumes my generator going from inside the loop to outside. Please note that I am not talking about the yielded values, or the for-loop that creates them. I left them there to show my intent with the function. The iterprint function is there to show that the generator gets consumed just moving from inside the loop to outside. I know this one is easy to dismiss to my consuming the generator with the iterprint, as this would be a common mistake. James -- James Stroud UCLA-DOE Institute for Genomics and Proteomics Box 951570 Los Angeles, CA 90095 http://www.jamesstroud.com -- http://mail.python.org/mailman/listinfo/python-list
