> On Wed, 06 Feb 2008 17:32:53 -0600, Robert Kern wrote:
>
> > Jeff Schwab wrote:
> ...
> >> If the strings happen to be the same length, the Levenshtein distance
> >> is equivalent to the Hamming distance.
Is this really what the OP was asking for. If I understand it correctly,
Levenshtein distance works out the number of edits required to transform
the string to the target string. The smaller the more equivalent, but with
the OP's problem I would expect
table1 table2
brian briam
erian
I think the OP would like to guess at 'briam' rather than 'erian', but
Levenstein would rate them equally good guesses?
I know this is pushing it more toward phonetic alaysis of the words or
something similar, and thats orders of magnitude more complex.
just in case,
http://www.linguistlist.org/sp/Software.html#97
might be a good place to start looking into it, along with the NLTK
libraries here
http://nltk.sourceforge.net/index.php/Documentation
Matt.
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