Denis Bilenko wrote:
> Raymond Hettinger wrote:
>> If positions 0 and 1 are optional, how do you expect to know whether
>> "path" is going to be at position 2? This problem doesn't exist with
>> dictionaries because the presence or absence of optional entries does
>> not affect the key reference to other entries. Accordingly, I
>> wouldn't expect that dict.get() would have a parallel list.get() with
>> plausible use cases.
>
> If you want to fill position 2, then positions 0 and 1 are mandatory.
> It is the simplest possible option parsing, I didn't said it was the
> most flexible :)
d = dict(enumerate(args))
print d[0], d[1], d.get(2)
Stefan
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