On Thu, 07 Feb 2008 19:14:54 +1100, bambam wrote:
> I started with ths:
> ------------------------------
> def open_pipe():
> pipe=PIPE()
> print pipe
> return pipe
>
> pipe=open_pipe()
> pipe.parent = self.parent
> print pipe
> ------------------------------
> It didn't do what I wanted: when I printed the pipe the second time it was
> not the same object as the first time.
Please post actual minimal code that reproduces the problem and a better
description of what you get and what you expected instead.
What is `PIPE` and where does `self` come from? What are the too
``print``\s printing that makes you think `pipe` isn't bound to the same
object?
> So I changed it to this:
> def open_pipe(pipe):
> pipe=PIPE()
> print pipe
>
> pipe = None
> open_pipe(pipe)
> pipe.parent = self.parent
> print pipe
>
> It still doesn't do what I wanted: I can't assign the parent property
> because pipe type is None.
Yes because in `open_pipe()` you bind a new object to the local name
`pipe` which of course has no effect on the binding of the name `pipe` in
the callers namespace.
> I'm not sure enough of what I am doing to tell if I have another error in
> my code causing the problem. Is either of these examples supposed to work
> as shown? Is it clear that either example is obviously wrong?
The second is wrong. The first should work if `self` and `PIPE` are bound
to appropriate objects.
Ciao,
Marc 'BlackJack' Rintsch
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