On Tue, 29 Jan 2008 11:51:04 -0800 (PST)
[EMAIL PROTECTED] wrote:
> Any elegant way of breaking out of the outer for loop than below, I
> seem to have come across something, but it escapes me
>
> for i in outerLoop:
> for j in innerLoop:
> if condition:
> break
> else:
> continue
> break
Ha! Think outside the box to begin with ...
P.
def cross(args):
ans = [[]]
for arg in args:
ans = [x+[y] for x in ans for y in arg]
return ans
def test():
L = [[0,1,2]]*3
for a,b,c in cross(L):
print a,b,c
if __name__=='__main__':
test()
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