d = {}?
? for line in input:?
? key, value = line.split(',').rstrip('\n')?
? d[key] = value?
Thanks. That worked except for the rstrip. So I did this:
for line in input:
? line = string.rstrip(line, '\n')
? key, value = line.split(',')
? dictionary[key] = value
Thanks again,
Tony
-----Original Message-----
From: Tim Chase <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Cc: python-list@python.org
Sent: Wed, 23 Jan 2008 3:37 pm
Subject: Re: Automatically Writing a Dictionary
> input = "/usr/local/machine-lang-trans/dictionary.txt"?
> > input = open(input,'r')?
> > dict = "{"?
> for line in input:?
> ? tup = re.split(','line)?
> ? dict += '"' + tup[0] +'":"' + tup[1] +'", '?
> dict += "}"?
> input.close()?
> > > Of course, that will just give me a string. How do I convert?
> it to, or make from scratch, a dictionary of that??
?
Don't bother with the string (and as a side-note, it's bad style to mask the
built-in dict() so I'll use "d"):?
?
? d = {}?
? for line in input:?
? key, value = line.split(',').rstrip('\n')?
? d[key] = value?
?
or even just?
?
? d = dict(line.split(',').rstrip('\n')?
? for line in input)?
?
using the aforementioned dict() function :-)?
?
You may want to clean it up a bit in case there are spurious leading/trailing
spaces to be trimmed:?
?
? from string import strip?
? d = dict(map(strip, line.split(','))?
? for line in input)?
?
or even ignore lines with the wrong number of commas:?
?
? d = dict(map(strip, line.split(','))?
? for line in input?
? if line.count(',') == 1)?
?
or assume any extra commas are part of the value:?
?
? d = dict(map(strip, line.split(',',1))?
? for line in input?
? if line.count(',') > 0)?
?
HTH,?
?
-tkc?
?
?
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