On Fri, 25 Jan 2008 05:49:40 -0800, rndblnch wrote: > def f(**kwargs): > <skipped> > return result > > such as : > f(x=12, y=24) == ['x', 'y'] > f(y=24, x=12) == ['y', 'x'] > > what i need is to get the order of the keyword parameters inside the > function. > any hints ?
Impossible. Dictionaries are unordered. Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list