Re: isgenerator(...) - anywhere to be found?

[Stefan Rank]

on 22.01.2008 14:20 Diez B. Roggisch said the following:
> 
> def isgenerator(v):
>     def _g(): yield
>     return type(v) == type(_g())
> 
> But I wonder why there is no such method already available?


This tests for generator objects, and you could also use::

   return type(v) is types.GeneratorType

I think that this is pretty direct already.

I also need to test for generator functions from time to time for which 
I use::

   def _isaGeneratorFunction(func):
       '''Check the bitmask of `func` for the magic generator flag.'''
       return bool(func.func_code.co_flags & CO_GENERATOR)


cheers,
stefan

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