On Jan 18, 12:08 pm, Madhur <[EMAIL PROTECTED]> wrote:
> On Jan 18, 2:37 pm, Chris <[EMAIL PROTECTED]> wrote:
>
>
>
> > On Jan 18, 11:23 am, Madhur <[EMAIL PROTECTED]> wrote:
>
> > > I would like to know the best way of generating filter of two files
> > > based upon the following condition
>
> > > I have two files. Contents of the first file is
>
> > > File 1
> > > abc def hij
> > > asd sss lmn
> > > hig pqr mno
>
> > > File 2
>
> > > jih def asd
> > > poi iuu wer
> > > wer pqr jjj
>
> > > I would like have the output as
> > > Output
>
> > > File1
> > > asd sss lmn
> > > File2
> > > poi iuu wer
>
> > > Basically I want to compare the two files based on second column. If
> > > the second
> > > column matches on both the files do not print anything, else if there
> > > is no matc
> > > h in for the second column for first file in second file then print it
> > > under Fil
> > > e1 header, else if there is no match for the second column for second
> > > file in fi
> > > rst file print it under File2 header.
>
> > > Thankyou
> > > Madhur
>
> > file1 = open('file1.txt','rb')
> > file2 = open('file2.txt','rb')
>
> > file1_line = file1.next()
> > file2_line = file2.next()
>
> > while file1_line and file2_line:
> > try:
> > f1_col2 = file1_line.split(' ')[1]
> > except IndexError:
> > print 'Not enough delimiters in line.'
> > try:
> > f2_col2 = file2_line.split(' ')[2]
> > except IndexError:
> > print 'Not enough delimiters in line.'
>
> > if f1_col2 != f2_col2:
> > outfile_data_to_relevant_files()
>
> > file1_line = file1.next()
> > file2_line = file2.next()
>
> > HTH
> > Chris
>
> If the files2 is unordered, then the above logic does not work. How to
> takle it?
Take a look at *nix's sort command, it can also sort based on a key
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