Re: __getitem__ on new-style classes

[Michael Spencer]

[EMAIL PROTECTED] wrote:
What i'm trying to do is tie special methods of a "proxy" instance
to another instance:
...
new style classes:
def test2():
  print "test2"
  class Container(object):
    def __init__( self, data ):
      self.data = data
#      self.__dict__["__getitem__"] = self.data.__getitem__
      self.__setattr__( "__getitem__", self.data.__getitem__ )
  data = range(10)
  c = Container(data)
  print
  print c.__getitem__(3) # works OK
  print c[3] # fails

I get a "TypeError: unindexable object". It
seems that c[] does not call __getitem__ in this case.
because __getitem__ is looked up in the class, not the instance dictionary
The plot thickens, however, when one tries the following:
def test3():
  data = range(10)
  c = type( "Container", (), { "__getitem__":data.__getitem__ } )()
  print "test3"
  print c[3]
Here you've created an entry in the class dictionary, just like writing
data = range(10)
class Container(object):
    __getitem__ = data.__getitem__
but, this probably doesn't help you much if you want the method to delegate to 
an attribute of the instance, since the instance is unavailable at class 
definition time

So, one solution, is to use create a delegating descriptor, like so:
class Delegate(object):
    def __init__(self, attrname):
        self.attrname = attrname
    def __get__(self, obj, cls):
        if isinstance(obj, cls):
            # Note that the attribute is looked up on obj._data
            return getattr(obj._data, self.attrname)
        else:
            return self
class Example(object):
    __getitem__ =  Delegate("__getitem__")
    def __init__(self, delegate):
        self._data = delegate
 >>> e = Example(range(10))
 >>> e[3]
 3
Michael
--
http://mail.python.org/mailman/listinfo/python-list