2008/1/16, Diez B. Roggisch <[EMAIL PROTECTED]>:
> Dmitry wrote:
>
> > Hi All,
> >
> > I've trying to develop one Python application, and
> > neet to solve one problem. I need to list all classes defined in one
> > package (not module!).
> >
> > Could anybody please show me more convinient (correct) way to
> > implement this?
>
> Look at the module inspect and it's predicates. Something like
>
>
> for name in dir(module_or_package):
> if inspect.isclass(getattr(module_or_package, name)):
> print "%s is a class" % name
>
>
> Diez
> --
> http://mail.python.org/mailman/listinfo/python-list
>
You should be able to adapt this one. You need to pass a directory to
it (warning: directory names including dots will cause you errors):
import os
import sys
import pyclbr
def pkg_modules(package):
return filter(lambda x: x.endswith(".py"), os.listdir(package))
def module_classes(module):
dict = pyclbr.readmodule_ex(module, [])
objs = dict.values()
objs.sort(lambda a, b: cmp(getattr(a, 'lineno', 0),
getattr(b, 'lineno', 0)))
print module
for obj in objs:
if isinstance(obj, pyclbr.Class):
print " class %s %s line: %d" % (obj.name, obj.super, obj.lineno)
def pkg_classes(package):
for module in pkg_modules(package):
module_classes("%s.%s" % (package, module[:-3]))
if __name__ == "__main__":
pkg_classes(sys.argv[1])
--
-- Guilherme H. Polo Goncalves
--
http://mail.python.org/mailman/listinfo/python-list
