Both of you are correct. >>> x = set([1,2,3]) >>> y = set([4,5]) >>> x |= y >>> x set([1, 2, 3, 4, 5])
On Jan 15, 2008 11:07 AM, Skip Montanaro <[EMAIL PROTECTED]> wrote: > > > Why is that? Doesn't the |= operator essentially map to an update() call? > > > > No, according to 3.7 Set Types, s | t maps to s.union(t). > > I was asking about the |= assignment operator which according to the > docs *does* map to the update method. > > Skip > > > > > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
