I have gotten a little further, but not in the order of the original
list
def divide_list(lst, n):
return [lst[i::n] for i in range(n)]x = [1,2,3,4,5,6,7,8,9,10] y = 3 z = divide_list(x,y) print z[0] print z[1] print z[2] this prints: [1, 4, 7, 10] [2, 5, 8] [3, 6, 9] closer, but I would like to maintain the original order of the list. -- http://mail.python.org/mailman/listinfo/python-list
