> What does "y=y" and "c=c" mean in the lambda function?
the same thing it does in a function definition:
def myfunct(a, b=42, y=3.141):
pass
> #################
> x = 3
> y = lambda x=x : x+10
>
> print y(2)
> ##################
>
> It prints 12, so it doesn't bind the variable in the outer scope.
You're mostly correct, as it does pull it out of the local
context. Try
x = 3
y = lambda x=x: x+10
print y(2)
print y()
to get "12" then "13" back.
-tkc
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