Robert Latest <[EMAIL PROTECTED]> wrote: > Hrvoje Niksic wrote: > > > keywords[:] = (s for s in keywords if s) > > Looks good but is so far beyond my own comprehension that I don't dare > include it in my code ;-)
:-) Worth understanding thought I think - here are some hints keywords[:] = (s for s in keywords if s) is equivalent to this (but without creating a temporary list) keywords[:] = list(s for s in keywords if s) which is equivalent to keywords[:] = [s for s in keywords if s] This keywords[:] = .... Replaces the contents of the keywords list rather than making a new list. Here is a demonstration of the fundamental difference >>> a=[1,2,3,4] >>> b=a >>> a=[5,6,7] >>> print a, b [5, 6, 7] [1, 2, 3, 4] >>> a=[1,2,3,4] >>> b=a >>> a[:]=[5,6,7] >>> print a, b [5, 6, 7] [5, 6, 7] Using keywords[:] stops the creation of another temporary list. The other behaviour may or may not be what you want! -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick -- http://mail.python.org/mailman/listinfo/python-list
