Donn Ingle wrote:
> Hi,
> Well, I'm beat. I can't wrap my head around this stuff.
>
> I need to create a list that will contain objects sorted by a "name"
> property that is in the alphabetical order of the user's locale.
>
> I used to have a simple list that I got from os.listdir and I could do this:
> l = os.listdir(".")
> l.sort(locale.strcoll)
> Which would work fine.
>
> But now I need to make objects (of different stripes) for each of the
> filenames returned and then I want to collect them all into a main list and
> have *that* main list be sorted.
>
> I started some test code like this: I hope the odd characters show.
>
> # -*- coding: utf8 -*-
>
> class Test(object):
> def __init__(self,nam):
> self.name = nam
> def __cmp__(self, other):
> return cmp(self.name, other.name)
>
> l = [ Test("ABILENE.ttf"), Test("Årgate.ttf"), Test("årse.ttf"),
> Test("Ärt.ttf"), Test("MomentGothic.ttf"), Test("öggi.ttf"),
> Test("Öhmygawd.ttf")]
>
> import locale
>
> l.sort() # won't work -> locale.strcoll)
>
> for i in l: print i.name
>
>
> Can anyone give me a leg-up?
>
> \d
You need to use the key argument to the sort function as well as the
cmp argument:
import os, locale
locale.setlocale(locale.LC_ALL, 'NO')
class Test(object):
def __init__(self, name):
self.name = name
def __str__(self):
return self.name
fnames = [Test(fname) for fname in os.listdir('.')]
fnames.sort(cmp=locale.strcoll, key=lambda t:t.name)
for fname in fnames:
print fname
and the output was
abel.txt
aegis.txt
onsdag.txt
pysortdir.py
pysortdir.py~
ærlig.txt
ønske.txt
åbel.txt
aaron.txt
åte.txt
Which is even more correct than I hoped for -- in Norwegian, aa is
pronounced the same as å (which is the 29th letter in the Norwegian
alphabet) and is sorted according to pronunciation.
-- bjorn
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