*** SOLVED ***
Thanks, Eric. I've had luck with code along these lines:
# 1. Assume Text widget as instance variable: textView
# 2. Assume button with method, 'start', bound to it
def start(self, event=None):
"""
Starts the demo.
"""
# Print A-Z to widget, pausing 1/10 second between each letter
for aNumber in range(65, 91):
self.textView.insert(END, chr(aNumber))
self.textView.update_idletasks()
time.sleep(0.1)
The code does just what I want it to.
Mario
On Dec 12, 3:43 am, "Eric Brunel" <[EMAIL PROTECTED]> wrote:
> On Wed, 12 Dec 2007 02:58:37 +0100, mariox19 <[EMAIL PROTECTED]> wrote:
> > Are Tkinter widgets running on their own thread?
>
> No. And usually, GUI toolkits and threads don't mix well...
>
>
>
> > If I try to make a simple application that will print the letters A to
> > Z to a Tkinter Text widget, and I space the printing of each letter by
> > 1 second, it seems no text will appear in the Text widget until the
> > method exits.
>
> > Take a look at this snippet:
>
> > # Assume I have created no threads other than the one that comes
> > with Main
>
> > def printToTkinterTextWidget(text):
> > """
> > Prints A-Z to the Text widget, 1 letter per second.
> > """
> > # Problem: no text appears in the widget until 26 seconds has
> > elapsed
> > for aNumber in range(65, 91):
> > self.textWidget.insert(END, text)
> > time.sleep(1)
>
> time.sleep will not give back the control to the Tkinter mainloop, so your
> text widget won't be refreshed on screen. Try:
> self.textWidget.update_idletasks()
> before the sleep.
>
> HTH
> --
> python -c "print ''.join([chr(154 - ord(c)) for c in
> 'U(17zX(%,5.zmz5(17l8(%,5.Z*(93-965$l7+-'])"
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