Re: parameter name conflict. How to solve?

[Steven Bethard]

Bo Peng wrote:
Dear list,
If you ask: why do you choose these names? The answer is: they need to 
be conformable with other functions, parameter names.

I have a function that pretty much like:
def output(output=''):
  print output
and now in another function, I need to call output function, with again 
keyword parameter output

def func(output=''):
  output(output=output)
Naturally, I get 'str' object is not callable. Is there a way to tell 
func that the first output is actually a function?
Yes, but you probably don't want to go that way.  Can you explicitly 
indicate the location of the 'output' function?  e.g.:

py> def output(output=''):
...     print output
...
py> def func(output=''):
...     __import__(__name__).output(output)
...
py> func('abc')
abc
or possibly:
py> def func(output=''):
...     globals()['output'](output)
...
py> func('abc')
abc
This is easier if output is in another module -- you can just write 
something like:
    outputmodule.output(output)

STeVe
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