kromakey a écrit :
> On 10 Dec, 19:11, Stargaming <[EMAIL PROTECTED]> wrote:
>> On Mon, 10 Dec 2007 16:10:16 +0200, Nikos Vergas wrote:
>>
>> [snip]
>>
>>>> Problem: In the dynamic language of your choice, write a short program
>>>> that will:
>>>> 1. define a list of the following user ids 42346, 77290, 729 (you can
>>>> hardcode these, but it should
>>>> still work with more or less ids)
>>>> 2. retrieve an xml document related to each user at this url "http://
>>>> api.etsy.com/feeds/xml_user_details.php?id="
>>>> 3. retrieve the data contained in the city element from each xml
>>>> document
>>>> 4. keep a running total of how many users are found in each city 5.
>>>> display the total count of users living in each city
>> [snip]
>>
(snip)
>
> A simpleton's version:
>
> #!/usr/local/bin/python
>
> import urllib
> from elementtree import ElementTree as et
>
> userids = [71234,729,42346,77290,729,729]
> url = 'http://api.etsy.com/feeds/xml_user_details.php?id='
>
> if __name__ == "__main__":
>
> city = {}
> for userid in userids:
> feed = urllib.urlopen(url+str(userid))
> tree = et.parse(feed)
> for elem in tree.getiterator('city'):
> if not city.has_key(elem.text):city[elem.text] = 1
> else: city[elem.text] += 1
> for k,v in city.items():
> if not k == None:print k,':\t',v
def count_users_by_city(url, userids):
urlopen = urllib.urlopen
parse = et.parse
cities = {}
for userid in map(str, userids):
feed = urlopen(url+userid)
tree = parse(feed)
for elem in tree.getiterator('city'):
key = elem.text
if key in cities:
cities[key] += 1
else:
cities[key] = 1
return cities
if __name__ == '__main__':
cities = count_users_by_city(url, userids)
print "\n".join("%s:%s" % item for item in cities.items())
Not tested !-)
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