En Thu, 06 Dec 2007 13:11:09 -0300, Bret <[EMAIL PROTECTED]> escribió:
> For completeness, what I ended up doing is this: > > server = SimpleXMLRPCServer((host, port)) > server.socket.settimeout(0.1) > > ServerWrapper became: > > def ServerWrapper(): > while True: > try: > server.handle_request() > if self.done.isSet(): > break > except timeout: > pass > > And that seems to do the trick! Giving the socket a timeout allows me > to check the Event more frequently and catch the change within a > reasonable time. Remember that the timeout applies to *all* socket operations; what if the XML request requires more than 0.1s to read? If handling large requests is more important than the delay at shutdown time, consider raising that value. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
